(x^2+1)(1)-(x)(2x+0)=0

Solution for (x^2+1)(1)-(x)(2x+0)=0 equation:

Simplifying
(x2 + 1)(1) + -1(x)(2x + 0) = 0

Reorder the terms:
(1 + x2)(1) + -1(x)(2x + 0) = 0

Reorder the terms for easier multiplication:
1(1 + x2) + -1(x)(2x + 0) = 0
(1 * 1 + x2 * 1) + -1(x)(2x + 0) = 0
(1 + 1x2) + -1(x)(2x + 0) = 0

Reorder the terms:
1 + 1x2 + -1x(0 + 2x) = 0
Remove the zero:
1 + 1x2 + -1x(2x) = 0

Remove parenthesis around (2x)
1 + 1x2 + -1x * 2x = 0

Reorder the terms for easier multiplication:
1 + 1x2 + -1 * 2x * x = 0

Multiply -1 * 2
1 + 1x2 + -2x * x = 0

Multiply x * x
1 + 1x2 + -2x2 = 0

Combine like terms: 1x2 + -2x2 = -1x2
1 + -1x2 = 0

Solving
1 + -1x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1x2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1x2 = 0 + -1
-1x2 = 0 + -1

Combine like terms: 0 + -1 = -1
-1x2 = -1

Divide each side by '-1'.
x2 = 1

Simplifying
x2 = 1

Take the square root of each side:
x = {-1, 1}